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Math Help - Hyperbola

  1. #1
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    Hyperbola

    Can you guys help me illustrate the transverse axis, a, b , vertices, directrix, latus rectum, etc. of this hyperbola
    16x^2 - 9y^2 - 64x - 18y - 89 = 0

    with standard equation of (x-2)^2 over 9 - (y+1)^2 over 16 = 1

    Thanks!
    Last edited by reiward; March 24th 2010 at 02:42 AM.
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  2. #2
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    Quote Originally Posted by reiward View Post
    Can you guys help me illustrate this hyperbola
    16x^2 - 9y^2 - 64x - 18y - 89 = 0

    with standard equation of (x-2)^2 over 9 - (y+1)^2 over 16 = 1
    Rewrite the equation as
    16x^2 - 64x +a^2 - 9y^2 - 18y + b^2 = 89 + a^2  + b^2 + 1
    You have to find the value of a and b such that
    16(x  - a)^2 - 9(y - b)^2 = 90 + a^2 + b^2
    Now rearrange the terms to get the required result.
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