# Straight Line equation in 4th quadrant of cartesian coordinate system

• Mar 16th 2010, 10:26 PM
drv123
Straight Line equation in 4th quadrant of cartesian coordinate system
Hi all,

Thanks for the attention. I want to know the staight line equation for 4th quadrant of cartesian coordinate system. Also i need to find out the slope of the straight line and Y intercept or X intercept constant, which ever is applicable to the staight line equation.

Thanks,
drv
• Mar 16th 2010, 10:43 PM
sa-ri-ga-ma
Quote:

Originally Posted by drv123
Hi all,

Thanks for the attention. I want to know the staight line equation for 4th quadrant of cartesian coordinate system. Also i need to find out the slope of the straight line and Y intercept or X intercept constant, which ever is applicable to the staight line equation.

Thanks,
drv

Hi drv123, welcome to MHF.
When the straight line is in the fourth quadrant, intercepts on the x and y axis will be either x1 and y1 or -x1 and -y1. And the angle made by the line with x -axis is obtuse. So the slope is negative. One point on the x-axis will be either (x1,0) or (-x1,0)
Then the equations of line will be
y = -(y1/x1)*(x-x1) or
y = -(y1/x1)*(x+x1)
• Mar 17th 2010, 12:24 AM
drv123
Hi Sa-re-ga-ma,