Quadrilateral is inscribed in a circle, where the tangents to this circle at points and intersect on the straight line joining and . Show that:
Thanks in advance.
If P is the point of intersection of two tangents at B and D and the line CA, then
PB = PD. You can easily show that the triangles PBA and PBD are congruent. Similarly Triangles PBC and PDC arfe also congruent.
Now proceed further to get the required result.