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Math Help - Angle between radius vector and tangent line

  1. #1
    Senior Member Pinkk's Avatar
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    Angle between radius vector and tangent line

    Prove that in polar coordinates for any given point P on the curve r=f(\theta), the angle \omega from the radius vector CP to the tangent line at P is given by tan(\omega) = \frac{r}{r'}

    I understand the proof given here if we assume the given lengths, but I can't make out the diagram and I don't understand why the given lengths are true; why PR = \rho sin(\Delta \theta) for instance. Could someone provide a better diagram or explain it? Thanks.


    http://wstein.org/home/wdj/teaching/...us_vector.html
    Last edited by Pinkk; March 16th 2010 at 12:05 PM.
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  2. #2
    Senior Member Pinkk's Avatar
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    Any help would be appreciated thanks.
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