In a convex quadrilateral $\displaystyle ABCD$, $\displaystyle AB=BC+DA.$ Bisectors of ABC and BAD meet at $\displaystyle P$. Show that $\displaystyle CP=DP$.

Sadly, no ideas on this one.

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- Mar 10th 2010, 01:17 PMatreyyuQuadrilateral identity
In a convex quadrilateral $\displaystyle ABCD$, $\displaystyle AB=BC+DA.$ Bisectors of ABC and BAD meet at $\displaystyle P$. Show that $\displaystyle CP=DP$.

Sadly, no ideas on this one. - Mar 10th 2010, 11:28 PMearboth