In a convex quadrilateral $\displaystyle ABCD$, $\displaystyle AB=BC+DA.$ Bisectors of ABC and BAD meet at $\displaystyle P$. Show that $\displaystyle CP=DP$.
Sadly, no ideas on this one.
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In a convex quadrilateral $\displaystyle ABCD$, $\displaystyle AB=BC+DA.$ Bisectors of ABC and BAD meet at $\displaystyle P$. Show that $\displaystyle CP=DP$.
Sadly, no ideas on this one.