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Math Help - Existence of a traingle that can be cut to 2005 conruent trianlges..

  1. #1
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    Thumbs down Existence of a traingle that can be cut to 2005 conruent trianlges..

    Prove that such a triangle exists that can be fully cut to 2005 congruent triangles...

    Well, this is wht I first did, I imagined an equilatoral triangle, joined the 3 mid points and obtained a fractel like the MHF symbol, but the problem is, the total no. of tiranlges is always a power of y4 so I cant get 2005 in the picture

    another way I know of to divide trianlges is by joining the vertices to the incentre of the equilatoral trianlge, but then we'll get powers of 3..

    Does such a trianlge really exist??
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  2. #2
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    Are you SURE 2005 is asked for, not 2025 ?
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  3. #3
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    Quote Originally Posted by Wilmer View Post
    Are you SURE 2005 is asked for, not 2025 ?

    Why do you think 2025? Can you prove it if it was 2025?
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  4. #4
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    2025 is a square; will work with equilateral triangle;
    rows of 1,3,5 ...
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