# Thread: Two circles intersecting each other...

1. ## Two circles intersecting each other...

Two circles intersect each other at A and B as shown in the figure. The common chord AB is produced to meet a common tangent PQ to the circles at D. Prove that DP=DQ.

2. hi snighda,

the attachment shows a general case.

3. Originally Posted by snigdha
Two circles intersect each other at A and B as shown in the figure. The common chord AB is produced to meet a common tangent PQ to the circles at D. Prove that DP=DQ.
It follows from the alternate segment theorem that the triangles PDB and ADP are similar. Deduce that $PD^2 = AD*BD$. (In fact, this is a well-known theorem: from a point D, draw a tangent DP to a circle, and a chord DBA cutting the circle; then the square of PD is equal to the product of DA and DB.)

Now do the same for the other circle, to see that $QD^2$ is also equal to $AD*BD$. Conclusion: PD = QD.

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### In figure. Two circles intersect each other at A and B .the common chord AB is produced to meet the common tangent PQ to the circle at D. Prove that DP = DQ.

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