In the figure given below, ABC is an isosceles triangle in which AB=AC. Also D is a point such that BD=CD. How do I prove that AD bisects angle A & angle D?
This is what I have done:
Consider the triangles ABD & ACD.
AD=DA (common side)
Thus the triangles ABD & ACD are congruent by Side-Side-Side (SSS) congruence rule but how do I prove that AD bisects angle A & angle D?