i need to find the volume of this beaker
other than the information given in the picture, you are also told that the diameter of the opening is 1.2. I could not figure out the radius of the spherical part to find the total volume of the beaker
A rough guide would be -
7.3cm high for the spherical part, hence a radius of 4.65cm.
Volume of the bottom is
= 421.16cm^3 for the sphere.
Finding the volume of the cylindrical top assuming a radius of 0.6cm and a height of 4.7cm. This gives ~5.32cm^3
Total volume around 426.48cm^3. This doesn't take into account inaccuracies such as doubling up on the joint where the sphere and cylinder meet etc, but it's hardly an accurate drawing to work off to begin with.
thank you to everbody who helped me with this question i appreciate it. Sorry to be more of a pain but i got a couple of surface area questions that i need help with.
A 21.3 cm diameter hole is drilled in a cube with 48.4 cm long sides as shown here (sketch is not to scale). Determine the total surface area of this shape in square centimeters.
Express your answer to three significant digits.
A tank used to transport liquids is made up of a cylinder with semi-spheres on its ends as shown (drawing not to scale). The length of the cylindrical portion of the tank is 2.2 m and its height is 2.1 m. What is the surface area of the outside of the tank in square metres?
Reference Pic: http://img710.imageshack.us/img710/1430/83625107.png
I did the second question and got 49.8. I wanted to know if this was the right answer, if it is not how do i get to the right answer.
thanks in advance
to Q1: The total surface of this solid consists of:
A = (surface of cube) - 2(base circles of cylinder) + (curved surface of cylinder)
Let s denote the length of the edge of the cube and r the radius of the base circle of the cylinder which have of course the height s then you get:
Plug in the known values!
to Q2: I'm very interested to learn how you got this result.
The radius of the cylinder and the sphere is r = 1.05 m, the length of the cylinder is l = 2.2 m.
The the surface area consists of the curved surface area of the cylinder and the surface of a complete sphere:
Plug in the values you already know. I've got A = 28.369 mē
- the curved surface of the cylinder that means without the circle at the base and at the top.
- and the surface of a complete sphere that means without the circle at the base.
If you use the formulas for the surface area of a complete cylinder and a complete semi-sphere then your result must be too large.