The vertices of a triangle are at A(-3,-2), B(2,1) and C(0,6). What is the equation of the two lines.
Please help me and show the solution... Thanks!
Can you handle this? If not ask for some extra help.
Draw a horizontal thru Ameeting the y axis @0,-2.Label pointD. ACD is now the slope diagram for line AC Rise is 8, run is 3,slope is 8/3.Distance between A and C is sq.root 73 (d^2=3^2+8^2)
Draw a perpendicular from B to AC meeting AC@K.Slope of BK is the negative inverse of line AC=to -3/8
Equation of line AC from y=mx+b isy=8/3x+6
Equation of BK Use point slope formula where point is 2,1
if a=b and a=c b=c
x=-1.4 and y=2.3
using these coordinates the slope for BK is 1.3/3.4 from whence the lenght of Bk =3.64. You can now calculate the area of ABC.This is more than you needed for an answer but i believe you needed it