Ok, so I'm trying to post on some forums, and I came up against a hell of a problem. I tried it many ways round, and here is my most perfect, most recent attempt:
As you can see, h<<r. That really shouldn't be happening, seeing as the thing's gonna be longer than it is wide.
Look at a preview of a Raven. It'll say its length in the top-left corner.
Now look at the attributes of a cruise missile. 0.1m^3 or something volume. How long can the thing be at that volume? According to http://science.howstuffworks.com/cruise-missile2.htm 6.25h=0.26r (6.25m long, h in standard notation, .52m wide, d in standard notation, d=2r, r=d/2, r=.52/2=.26) is implied.
Assuming a perfectly cylindrical cruise missile, we can work some **** out.
V is volume.
thus 0.1=(pi)(r^2)0.0416r (Substitute out h in terms of r.)
thus ((0.1/0.0416)/(pi))^(1/3)=r = 0.9146443701959527 (According to Python. Good enough for EVE, good enough for me.)
thus h=0.0416*[that mess three lines up]
If anyone could point me in the right direction, I have several cookies on offer, because damn, cookies win.