# Math Help - Confused with this triangle question...

1. ## Confused with this triangle question...

A right triangle has one leg four times as long as the other.
Write its perimeter P in terms of the length x of the shorter leg.

A right triangle has one leg four times as long as the other.
Write its perimeter P in terms of the length x of the shorter leg.
hi

if the shorter leg is x , then the longer leg is 4x and since its a right triangle , you can use the phythagoras theorem to find its hypothenus which is $x\sqrt{17}$ , so

p= $x\sqrt{17}$+x+4x

3. I don't get that, MA.
Hypotenuse = SQRT(x^2 + (4x)^2) = SQRT(x^2 + 16x^2) = xSQRT(17)

Perimeter = x + 4x + xSQRT(17) = x(5 + SQRT(17))

4. Originally Posted by Wilmer
I don't get that, MA.
Hypotenuse = SQRT(x^2 + (4x)^2) = SQRT(x^2 + 16x^2) = xSQRT(17)

Perimeter = x + 4x + xSQRT(17) = x(5 + SQRT(17))
hi Wilmer , yeah of course ! Thanks for spotting that