A, B, C, D are points on a circle of centre O and TA is the tangent to the circle at A.
TA = 7.1 cm
AD = 4.5 cm
Basically if we were to draw this circle we would first draw (Clockwise) the point D on the circle then A then C and then B.
Point T being outside of the circle slightly on the right of it.
Now angle BDA = 36 degrees and DAT = 28 degrees
From this info I need to find the radius of the circle and say if OT bisects AD?
I have demonstrated (using the circle property) that angle BOA = 72 degrees and BCA = 144 degrees and also OAD = 62 degrees.
But how can I find the radius and prove the bisection? Please any hints or answers to this treaky one :-)