Hey Everyone,
I have a question here that asks:
Prove the Law of Sines for triangle ABC:
sinA/a = sinB/b = sinC/c
We have looked at all the side and angle axioms and up to euclidean geometry, any help here would be greatly appreciated. Thanks guys.
You can prove the Law of Sines by starting with a triangle consisting of vectors A,B, and C. This means means that A+B+C=0. Then take the cross product of both sides with vector A to get the first part of the relation. Do the same thing with vector B to get the second part of the relation.
Hello, GreenDay14!
Here is the classic textbook proof.Prove the Law of Sines for triangle ABC: .Code:C * *| * * | * b * | * a * |h * * | * * | * * | * A * - - - * - - - - - - - * B D
Draw altitude to side
. . Call it
In right triangle .[1]
In right triangle .[2]
Equate [1] and [2]: .
In a similar fashion, we can prove that: .