Therefore angle CAO is 90-37=53 degrees.
Triangle AOC is isosceles as two sides are radius length.
Therefore angle CAO=angle OCA.
Also side AC is perpendicular to side OM.
Angle CBA=37 degrees, so angle MAO is 90-37=53 degrees.
Therefore angle MCO=53 degrees, angle MOC=37 degrees.
Or angle BCA is 90 degrees.
Angle OMA is 90 degrees, therefore line OM is parallel to side BC.
Hence angle OMA=angle BAC.
Triangle OCA is isosceles and is split into 2 identical right angled triangles.
Therefore angle MOA=angle MOC.