a rhombus has sides of length 10 inches, and the lengths of its diagonals difference by 4 inches . what is the area of the rhoumbus in square inches ?
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Originally Posted by sri340 a rhombus has sides of length 10 inches, and the lengths of its diagonals difference by 4 inches . what is the area of the rhoumbus in square inches ? Area = half of the product of the diagonals. To get the length x of the shorter diagonal, note that the diagonals of a rhombus are perpendicular to each other. Therefore: $\displaystyle x^2 + (x - 2)^2 = 10^2$.
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