Please help with the following problem: in triangle ABC let points D and E be the midpoints of sides AB and AC. Show DE must be half the length of BC. Thank you, mdk
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Originally Posted by mdk Please help with the following problem: in triangle ABC let points D and E be the midpoints of sides AB and AC. Show DE must be half the length of BC. Thank you, mdk $\displaystyle \triangle ABC$ is congruent to $\displaystyle \triangle ADE$, then we have $\displaystyle \frac{AD}{AB} = \frac{DE}{BC}$ $\displaystyle \frac{1/2 AB}{AB} = \frac{DE}{BC}$ $\displaystyle DE = \frac{1}{2}BC$
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