• February 2nd 2010, 02:46 AM
fishlord40
A chord of the parabola that is perpendicular to the axis and 1 unit from the vertex has a length of 1 unit. How far is the vertex from the focus?

***by the way, the answer to this problem is 1/16. I just want to know how did you get the right answer to this problem. thanks!!
• February 2nd 2010, 03:51 AM
earboth
Quote:

Originally Posted by fishlord40
A chord of the parabola that is perpendicular to the axis and 1 unit from the vertex has a length of 1 unit. How far is the vertex from the focus?

***by the way, the answer to this problem is 1/16. I just want to know how did you get the right answer to this problem. thanks!!

1. Let the equation of the parabola be

$4py = x^2$

where p is the distance of the focus from the vertex.

2. You know the coordinates of 2 points of the parabola: $P(-\tfrac12, 1)$, $Q(\tfrac12, 1)$

3. Plug in the coordinates of Q into the equation of the parabola and solve for p:

$4p \cdot 1 = \left(\frac12\right)^2$