Write the eq. of the circle having its center on the line x=2 and passing through the

point of intersection between the circles of x^2+y^2-3x=0 and x^2+y^2=3y.

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- January 31st 2010, 03:58 AMjasonlewizequation of circle
Write the eq. of the circle having its center on the line x=2 and passing through the

point of intersection between the circles of x^2+y^2-3x=0 and x^2+y^2=3y. - January 31st 2010, 04:29 AMArchie Meade
You mean "passing through the points of intersection".

Geometrically speaking,

you are looking for a point on the line x=2 that is equidistant from the two points of intersection of the circles, so that both points are a radius away.

Solve for the points of intersection of the circles.

Then use Pythagoras' theorem to find the y co-ordinate of the new circle centre.

Then find that circle's radius.

You can then write the circle equation.