I have a triangle (as per below figure)
the Known points are all the triangle distances ie A,B,C
The two vertices are known,x1,y1, x2,y2.
I require the third vertice formula / equation for x3 and y3
the angle are not known.(i do not need them now)
this is not a right angle triangle
i need this for my programming purpose
Please help me as soon as possible
The circle with center and radius C is given by and the circle with center [tex](x_2, y_2) and radius A is [tex](x-x_2)^2+ (y-y_2)^2= A^2, just as earboth said.
Multiply both of those out:
Subtract the two equations and the squares of both and cancel out:
You can solve that for y in terms of x:
.
Put that into the equation of either circle and you have one equation to solve for x. Of course, there will be two solutions, one on either side of the line between and .