Hi !

2. ## hint

Ops menth CDB

3. That's false.

$\triangle CDE$ is actually equilateral, thus $\measuredangle\,AEC=75^\circ.$ On the other hand we have that $\triangle BDF$ is also equilateral, then $\measuredangle\,D=90^\circ$ hence $\measuredangle\,FED=45^\circ.$

Finally $\measuredangle\,AEC+\measuredangle\,E+\measuredang le\,FED=180^\circ,$ which implies that $A,\,E$ and $F$ are collinear.

4. Originally Posted by Henryt999
Note that Ced is a right angle...
No, that angle = 60 degrees