# Help Géo !!

• January 30th 2010, 03:47 PM
Perelman
Help Géo !!
• January 30th 2010, 04:12 PM
Henryt999
hint
Ops menth CDB
• January 30th 2010, 05:18 PM
Krizalid
That's false.

$\triangle CDE$ is actually equilateral, thus $\measuredangle\,AEC=75^\circ.$ On the other hand we have that $\triangle BDF$ is also equilateral, then $\measuredangle\,D=90^\circ$ hence $\measuredangle\,FED=45^\circ.$

Finally $\measuredangle\,AEC+\measuredangle\,E+\measuredang le\,FED=180^\circ,$ which implies that $A,\,E$ and $F$ are collinear.
• January 30th 2010, 06:03 PM
Wilmer
Quote:

Originally Posted by Henryt999
Note that Ced is a right angle...

No, that angle = 60 degrees