Hi !

http://img204.imageshack.us/img204/1228/sanstitrehc.png

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- Jan 30th 2010, 03:47 PMPerelmanHelp Géo !!
- Jan 30th 2010, 04:12 PMHenryt999hint
Ops menth CDB

- Jan 30th 2010, 05:18 PMKrizalid
That's false.

$\displaystyle \triangle CDE$ is actually equilateral, thus $\displaystyle \measuredangle\,AEC=75^\circ.$ On the other hand we have that $\displaystyle \triangle BDF$ is also equilateral, then $\displaystyle \measuredangle\,D=90^\circ$ hence $\displaystyle \measuredangle\,FED=45^\circ.$

Finally $\displaystyle \measuredangle\,AEC+\measuredangle\,E+\measuredang le\,FED=180^\circ,$ which implies that $\displaystyle A,\,E$ and $\displaystyle F$ are collinear. - Jan 30th 2010, 06:03 PMWilmer