# Thread: Ratio of the areas of two similar triangles

1. ## Ratio of the areas of two similar triangles

The ratio of the areas of two similar triangles is 16:9. What is the ratio of the lengths of corresponding sides? Please show your work here.

2. Originally Posted by FHS93
The ratio of the areas of two similar triangles is 16:9. What is the ratio of the lengths of corresponding sides? Please show your work here.
Area of triangle 1 = 16
Area of triangle 2 = 9

Since area is the only one given I suppose that the triangle is an equilateral

get the sides of T1

16x4=64/square root of 3=36.95 then square the answer give you 6.08

get the sides of T2

9x4=36/square root of 3=20.78 then square the answer give you 4.56

Now get the ration T1:T2

6:5 ^^

3. Originally Posted by FHS93
The ratio of the areas of two similar triangles is 16:9. What is the ratio of the lengths of corresponding sides? Please show your work here.
You're expected to know and apply that if $\displaystyle L_1 = k L_2$ then $\displaystyle A_1 = k^2 A_2$.