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Math Help - volume

  1. #1
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    volume

    An aquarium has one end of width 10dm and height 8dm. It has some water in it. When the tank is tilted enough to cover the 10x8 end, the water covers three fourths of the base. How deep is the water in the tank is on a level table???


    HW please help
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  2. #2
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    Dear igottaquestion,

    Volume of water in the tank (If the base has a length of "h"dm)= \frac{1}{2}\times(\frac{3}{4}\times10h)\times{8} dm^3

    If the height of water on a level table is x,

    h\times{10}\times{x}=\frac{1}{2}\times(\frac{3}{4}  \times10h)\times{8}

    Then x=3dm

    Hope this helps.
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