Sorry about the link no one click it Idk what it is but its coming up in all my posts
"Find the length of the altitude of a right triangle.The hypotenuse is separated into lengths of 6 and 15"
Anyone can help me with some solving steps? I just don't know how to set it up; I don't get the whole geometric mean thing and how to apply it to these kind of problems
Find the length of the altitude of a right triangle.
The hypotenuse is separated into lengths of 6 and 15.Code:C * *| * * | * * | * * | * * |h * * | * * | * A * - - - * - - - - - - - - - - - * C 6 D 15
Angle C = 90°.
Altitude h = AD divides the hypotenuse into: AD = 6 and DC = 15.
That geometric mean theorem says: .h² .= .(6)(15)
. . . . . . . . . . . . . __ . . . . .__
Therefore: .h .= .√90 .= .3√10