1. ## Altitude Length

"Find the length of the altitude of a right triangle.The hypotenuse is separated into lengths of 6 and 15"

Anyone can help me with some solving steps? I just don't know how to set it up; I don't get the whole geometric mean thing and how to apply it to these kind of problems
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2. Sorry about the link no one click it Idk what it is but its coming up in all my posts
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3. Originally Posted by xolauren23x
Sorry about the link no one click it Idk what it is but its coming up in all my posts
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You should run some malware detection software on your machine.
ImPerfectHacker will probably advise when he is online.

RonL

4. Originally Posted by CaptainBlank
You should run some malware detection software on your machine.
ThePerfectHacker will probably advise when he is online.
What does that have to do with malware?

Sorry about the link no one click it Idk what it is but its coming up in all my posts
If you got infected then I can help.

5. Originally Posted by xolauren23x
"Find the length of the altitude of a right triangle.The hypotenuse is separated into lengths of 6 and 15"

Anyone can help me with some solving steps? I just don't know how to set it up; I don't get the whole geometric mean thing and how to apply it to these kind of problems
.
Is that the complete question? It seems not to make sense.

RonL

6. Hello, xolauren23x!

Find the length of the altitude of a right triangle.
The hypotenuse is separated into lengths of 6 and 15.
Code:
              C
*
*|  *
* |     *
*  |        *
*   |           *
*    |h             *
*     |                 *
*      |                    *
A * - - - * - - - - - - - - - - - * C
6   D          15

Angle C = 90°.
Altitude h = AD divides the hypotenuse into: AD = 6 and DC = 15.

That geometric mean theorem says: . .= .(6)(15)
. . . . . . . . . . . . . __ . . . . .__
Therefore: .h .= .√90 .= .3√10