centriod of trianlge

For a triangle, the centriod is just the "average" of the vertices. That is, if the vertices are $(x_1, y_1)$ , $(x_2, y_2)$ , and $(x_3, y_3)$ , in some coordinate system, then the centroid is at $\left(\frac{x_1+ x_2+ x_3}{3}, \frac{y_1+ y_2+ y_3}{3}\right)$ .

Of course, the midpoints of the sides are $\left(\frac{x_1+ x_2}{2}, \frac{y_1+ y_2}{2}\right)$ , $\left(\frac{x_2+ x_3}{2}, \frac{y_2+ y_3}{2}\right)$ , and $\left(\frac{x_1+ x_3}{2}, \frac{y_1+ y_3}{2}\right)$ . Use the formula above to find the centroid of that triangle.