# Thread: Need help finding a dimension.

1. ## Need help finding a dimension.

The question:

The density of aluminum is 2.70 g/cm^3. Calculate the thickness of a rectangular sheet of aluminum foil with a width of 11.5cm, a length of 14.0cm, and a mass of 2.04g.

2. Originally Posted by halpo
The question:

The density of aluminum is 2.70 g/cm^3. Calculate the thickness of a rectangular sheet of aluminum foil with a width of 11.5cm, a length of 14.0cm, and a mass of 2.04g.

Recall: $\displaystyle d=\frac{m}{v}$ or $\displaystyle d=\frac{m}{L\cdot{W}\cdot{T}}$

You were given:
$\displaystyle d=2.70$

$\displaystyle W=11.5$

$\displaystyle L=14.0$

$\displaystyle m=2.04$

So, finish up.

3. So,

(2.70) = (2.04 / 161T)

(2.70)(161T) = 2.04

434.7T = 2.04

T = (2.04 / 434.7)

T = .004693cm = .047mm

Are these steps (and the answer) correct? Thanks for the help.

4. Originally Posted by halpo
So,

(2.70) = (2.04 / 161T)

(2.70)(161T) = 2.04

434.7T = 2.04

T = (2.04 / 434.7)

T = .004693cm = .047mm

Are these steps (and the answer) correct? Thanks for the help.
Correct!