Hello - I did my best to post the graphic, assume all lines are parallel. Will you also be able to give an explanation?
Any help would be greatly appreciated!
Thank you,
Hello - I did my best to post the graphic, assume all lines are parallel. Will you also be able to give an explanation?
Any help would be greatly appreciated!
Thank you,
Not that easy to "explain"...I'll try:
label the 15 by 26 rectangle ABCD clockwise, A top left corner;
label end of line from D as E, end of line from C as F, so DE = CF = 39;
draw perpendicular EG, G on CF: so EG = x;
so we now have right triangles BCF and EGF: these are SIMILAR triangles
Since similar, then EG/EF = BC/CF : x/15 = 26/39 : x = 10
Hello Wilmer -
Thank you for your help...I labeled the diagram as you requested.
I am a bit confused about where you are placing "x"
Perpendicular to EG?
Thank you,