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Math Help - Unable to Solve Problem

  1. #1
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    Unable to Solve Problem

    Question: How many decorative bricks 10 inches long would be needed to go around a circular garden that is 8 feet in diameter? Use Pi = 3.14

    According to the book the answer is "about 30".

    This is what I did
    Step 1: I read the problem and decided that it is asking me to find the perimiter. I used the formula pi x d. The answer I got was 25.12. How did the author get 30? Am I doing something wrong? I have spent over an hour trying to figure it out.
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  2. #2
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    Quote Originally Posted by kidari View Post
    Question: How many decorative bricks 10 inches long would be needed to go around a circular garden that is 8 feet in diameter? Use Pi = 3.14

    According to the book the answer is "about 30".

    This is what I did
    Step 1: I read the problem and decided that it is asking me to find the perimiter. I used the formula pi x d. The answer I got was 25.12. How did the author get 30? Am I doing something wrong? I have spent over an hour trying to figure it out.
    8ft = 48in

    So the circumference is

    C = \pi D

     = 3.14 \times 48\,\textrm{in}

     = 150.72\,\textrm{in}.


    So i would say you would need about 16 x 10in bricks...


    Are you sure the question didn't say 8ft in radius? Because then you would need about 30... (32 in fact...)
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    Thank you =)
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