1. ## problem (Rectangular Parallelepiped)

1.) A container in the form of a rectangular parallelepiped having an altitude of 6m and a base of 10m by 8ft. is to be painted only on the outside surfaces. Compute for the number of cans of paint if a can covers an area of 12 sq. ft.

2.) How many gallons are needed to fill a pool 130ft long and 40 ft wide to a depth of 8ft. (231 cu in. = 1 gal.)

3.) A rectangular piece of cardboard 18 in. by 23 in. is made into a box with an open top by cutting a square of side 4 inches from each corner and folding up the sides. What is the volume of the box in cubic inches?

2. Originally Posted by orochimaru700
1.) A container in the form of a rectangular parallelepiped having an altitude of 6m and a base of 10m by 8ft. is to be painted only on the outside surfaces. Compute for the number of cans of paint if a can covers an area of 12 sq. ft.

2.) How many gallons are needed to fill a pool 130ft long and 40 ft wide to a depth of 8ft. (231 cu in. = 1 gal.)

3.) A rectangular piece of cardboard 18 in. by 23 in. is made into a box with an open top by cutting a square of side 4 inches from each corner and folding up the sides. What is the volume of the box in cubic inches?
I seriously doubt that a container is going to be measured in both metres and feet...

3. Hi Prove It, let's ommit the 1st question. Let's proceed to the 2nd and 3rd...

i'm having trouble with these problems. can u help...

4. Originally Posted by orochimaru700
1.) A container in the form of a rectangular parallelepiped having an altitude of 6m and a base of 10m by 8ft. is to be painted only on the outside surfaces. Compute for the number of cans of paint if a can covers an area of 12 sq. ft.

2.) How many gallons are needed to fill a pool 130ft long and 40 ft wide to a depth of 8ft. (231 cu in. = 1 gal.)

3.) A rectangular piece of cardboard 18 in. by 23 in. is made into a box with an open top by cutting a square of side 4 inches from each corner and folding up the sides. What is the volume of the box in cubic inches?
2) There are 12 inches to a foot.

So the dimensions of the pool are 1560in x 480in x 90in.

So the volume is $67\,392\,000\,\textrm{in}^3$.

Divide this by 231 to find out how many gallons of water.

3) Try drawing the net of the box.

You should see that the length of the box is 18 - 4 - 4 inches. So the length is 10 inches.

You should also see that the width is 23 - 4 - 4 inches. So the width is 15 inches.

The height is 4 inches.

What is the volume?

5. Volume = L x W x H, = 10 x 15 x 4

thanks for the help...

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# rectangular parallelepiped problems

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