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Math Help - Simple problem but no clue

  1. #1
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    Simple problem but no clue

    For finding the shape of the hyperbola, trace the equation \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1


    I have no clue what to do???
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  2. #2
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    Quote Originally Posted by TomJerry View Post
    For finding the shape of the hyperbola, trace the equation \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1


    I have no clue what to do???
    I suggest you Google hyperbola if you don't know how to draw a graph of this. Things to keep in mind include diagonal asymptotes and x-intercepts.
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  3. #3
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    Quote Originally Posted by TomJerry View Post
    For finding the shape of the hyperbola, trace the equation \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1
     \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1

    whereby

     c^2 = a^2 + b^2 .

    In your hyperbola, (h,k) = (0,0), so we have a start to this: The center is at the origin.

    Note that if

     \frac{(y-k)^2}{b^2} - \frac{(x-h)^2}{a^2} = 1

    then the transverse axis would be vertical. However, the way we have it, with the x-term positive and the y-term negative, the traverse axis is horizontal
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