For finding the shape of the hyperbola, trace the equation

I have no clue what to do???

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- Jan 6th 2010, 01:12 AMTomJerrySimple problem but no clue
For finding the shape of the hyperbola, trace the equation

I have no clue what to do??? - Jan 6th 2010, 02:15 AMmr fantastic
- Jan 6th 2010, 02:22 AMabender

whereby

.

In your hyperbola, (h,k) = (0,0), so we have a start to this: The center is at the origin.

Note that if

then the transverse axis would be vertical. However, the way we have it, with the x-term positive and the y-term negative, the traverse axis is horizontal