I always mess up these posts... (I'm a bad helper) Sorry...
I give up. I've tried different ways and to no avail, can someone please check my work, tell me where I went wrong and point me to the right direction?
Coordinates X- (3,36)
Y- (66, 69)
Z- (97, 74)
P – midpoint of ZY,
P 97 + 66 , 74 + 69
2 2
P 163 , 143
2 2
P ( 81.5 , 71.5 )
Q- midpoint of XZ,
Q 3 + 97 , 36 + 74
2 2
Q 100 , 110
2 2
Q (50 , 55)
R – midpoint of XY,
R 3 + 66 , 36 + 69
2 2
R 69 , 105
2 2
R (34.5 , 52.5)
Equation of line YR-
Y=mx + b
Y= 0.344x + b (97, 74)
Slope of line YR-
0.344
52.5 – 74 = -21.5 =
34.5 – 97 = -62.5 =
74 = 0.344 (97) + b
74 = 33.368 + b
b = 74 – 33.368
b = 40.632
Equation of line YR-
Y= 0.344x + 40.632
Slope of line YQ-
0.875
55 – 69 = -14 =
50 – 66 = -16 =
Equation of line YQ-
Y= 0.875x + b (66, 69)
69 = 0.875 (66) + b
69 = 57.75 + b
b = 69 – 57.75
b = 11.25
Equation of line YQ-
Y= 0.875x + 11.25
Equation of line XP-
Y = 0.452x + b ( 3, 36 )
Slope of line XP-
0.452
71.5 – 36 = 35.5 =
81.5 – 3 = 78.5 =
36 = 0.452 (3) + b
36 = 1.356 + b
b = 36 -1.356
b = 34.644
Equation of line XP-
Y= 0.452x + 34.644
-y + (-0.875x) = -11.25
y – 0.452x = 34.644
0.423x = 23.394
0.423 = 0.423
X= 55.305
Y – 0.452 (55.305) = 34.644
Y – 24.998 = 34.644
Y = 59.642
Point B – (55.305 , 59.642)
The coordinates of the circumcenter in triangle XYZ are (55.305, 59.642)
It's alright integral, you tried.
I tried a new method;
-63/33 (34.5, 52.5)
y - 52.5 = -1.909(x - 34.5)
y - 52.5 = -1.909x + 65.861
y = -1.909x + 118.361
-.161 ( 81.5 , 71.5)
y - 71.5 = -.161(x - 71.5)
y - 71.5 = -.161x + 11.512
y = -.161x + 83.012
Is anything correct, at all?
I got weird coordinates, please someone give me a step by step?