equilateral problem

• Jan 5th 2010, 12:46 PM
strunz
equilateral problem
Hi guys. Suppose we have an equilateral with the side = 4.
My book says that the height of an equilateral = $\frac{s\sqrt{3}}{2}$

And we get 4(1.4)/2 = 2.8 = h

Then let's say we divide the equilateral by its height. We then get two right triangles, each with the sides 2, and the hypotenuse 4. Now we want to calculate its height. We do

$2^2 + h^2 = 4 + h^2 = 16 = h^2 = 12$, and h is not equal to 2.8 (how do i type "not equal to"?).

What have I misunderstood?
• Jan 5th 2010, 02:43 PM
Dr. Jekyll
Quote:

Originally Posted by strunz
And we get 4(1.4)/2 = 2.8 = h

$\sqrt{3}=1.73205081$ and you got 1.4. Maybe that's the problem.