Results 1 to 2 of 2

Thread: Suspended compass

  1. #1
    Dec 2009

    Suspended compass


    A friend of mine showed this problem he translated from a physics olympiad but I can't solve it:
    "Suspended compass
    Consider a perfectly symmetrical compass. It is constituted by two rigorously equal connecting rods, that join in a vertex the one that we call pivot. The opening angle is regulable. Imagine that we suspend the compass for the tip of one of the connecting rods, attaching it to a wire whose other end is attached at the ceiling.
    a) Sketch the position of the bar at various angles of opening.
    b) What is the opening angle of the compass, so that the pivot is the highest possible?
    Hint: The center of mass of the bar, assuming that the rods have densities
    uniform is the point where the bisector of the angle of the bar crosses the line
    passing through the midpoint of both rods. The mass center has to be, for any angle of opening, in the vertical line of the point of suspension of the wire."

    Sorry for the english in the translation. My question is how do you solve this geometrically (I know it seems like physics but the problem is all about geometry)
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Opalg's Avatar
    Aug 2007
    Leeds, UK
    In the picture, the arms of the compasses, suspended from the point A, are AP and PB, with the pivot at P. The midpoints of AP and BP are L and M, and the centre of mass is at C, half way between L and M.

    If the length of AP is a, then PL = PM = a/2, so L and M both lie on a circle of radius a/2 centred at P. The point C is half way from L to M, so lies on circle of radius a/4 centred at the point X half way between P and L.

    The pivot point P will be highest when the angle between AP and the vertical line AC is greatest. That will happen when AC is tangent to the circle through P, C and L. Then ACX is a right angle, and the angle AXC is $\displaystyle \cos^{-1}1/3$ (because XC = a/4 and XA = 3a/4). But the angles AXC and APB are equal (because they are both equal to twice the angle LPC), so the answer to the problem is that the pivot is highest when the opening angle of the compasses is $\displaystyle \cos^{-1}1/3$.

    Linguistic note: In (British) English, a compass is a magnetic object that points north. The geometric object for drawing circles is usually called a pair of compasses.

    Physical note: It follows from the geometry that the pivot is highest when the arm PB of the compasses is horizontal. There is probably a good physical reason for this, but I don't see it. If you could use physics to see why this is true, then you could deduce very quickly that the angle is $\displaystyle \cos^{-1}1/3$, without having to do any geometry.
    Attached Thumbnails Attached Thumbnails Suspended compass-compasses.jpg  
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. suspended particle
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: Mar 3rd 2010, 08:57 PM
  2. compass question
    Posted in the Geometry Forum
    Replies: 2
    Last Post: Feb 12th 2010, 10:45 AM
  3. Objects suspended from table - tension
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: Sep 18th 2009, 03:21 PM
  4. compass directions
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: Sep 3rd 2008, 09:31 AM
  5. Ruler and compass construction 7-gon
    Posted in the Advanced Algebra Forum
    Replies: 4
    Last Post: Aug 21st 2008, 06:36 PM

Search tags for this page

Click on a term to search for related topics.

Search Tags

/mathhelpforum @mathhelpforum