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Math Help - Right Triangle Circumscribed Circle Proof

  1. #1
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    Smile Right Triangle Circumscribed Circle Proof

    Prove that the hypotenuse of a Euclidean right triangle is a diameter of the circumscribed circle.

    Given theorem: Let \triangle{ABC} be a triangle and let M be the midpoint of segment AB. If \angle{ACB} is a right angle, then AM = MC.

    I've drawn a diagram to help me but don't know where to begin on the proof.

    Right Triangle Circumscribed Circle Proof-circumscribed-circle.png
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  2. #2
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    Lightbulb I think I've got it

    I think I finally figured out how to do this.

    No help needed - THANKS!!!
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  3. #3
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by ReneePatt View Post
    Prove that the hypotenuse of a Euclidean right triangle is a diameter of the circumscribed circle.

    Given theorem: Let \triangle{ABC} be a triangle and let M be the midpoint of segment AB. If \angle{ACB} is a right angle, then AM = MC.

    I've drawn a diagram to help me but don't know where to begin on the proof.

    Click image for larger version. 

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    there is a theorem that said
    the circum angle established on the diameter equal 90 you can use this theorem

    and the converse of it is true the angle established on the diameter from the circum of the circle equal 90
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