# Right Triangle Circumscribed Circle Proof

• December 10th 2009, 09:54 AM
ReneePatt
Right Triangle Circumscribed Circle Proof
Prove that the hypotenuse of a Euclidean right triangle is a diameter of the circumscribed circle.

Given theorem: Let $\triangle{ABC}$ be a triangle and let M be the midpoint of segment AB. If $\angle{ACB}$ is a right angle, then AM = MC.

I've drawn a diagram to help me but don't know where to begin on the proof.

Attachment 14393
• December 11th 2009, 07:51 AM
ReneePatt
I think I've got it
I think I finally figured out how to do this.

No help needed - THANKS!!!
• December 11th 2009, 08:02 AM
Amer
Quote:

Originally Posted by ReneePatt
Prove that the hypotenuse of a Euclidean right triangle is a diameter of the circumscribed circle.

Given theorem: Let $\triangle{ABC}$ be a triangle and let M be the midpoint of segment AB. If $\angle{ACB}$ is a right angle, then AM = MC.

I've drawn a diagram to help me but don't know where to begin on the proof.

Attachment 14393

there is a theorem that said
the circum angle established on the diameter equal 90 you can use this theorem

and the converse of it is true the angle established on the diameter from the circum of the circle equal 90