Hello, ReneePatt!

Surely, you can do the first two . . .

Given three segments whose lengths are:

construct segments of lengths:

On a horizontal line, measure off: .

Code:

o - - - o - - - o - - -
O 1 P a Q

Through draw a diagonal line.

On the diagonal, measure off

Draw

Code:

*
*
*
R *
o
b * /
* /
* /
o - - - o - - - o - - -
O 1 P a Q

Through construct a line parallel to , cutting the diagonal at

Code:

S
o
x * /
* /
R * /
o /
b * / /
* / /
* / /
o - - - o - - - o - - -
O 1 P a Q

Then: .

**Proof**

From similar triangles: .

And we have: .