What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.
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Originally Posted by sri340 What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth. Hi all the preimeter is 31.7006 the complet solution sooner
Originally Posted by sri340 What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth. Hi sri340, Use the distance formula to calculate the lengths of each side. $\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ Then add them up.
Originally Posted by sri340 What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth. Hi all
Originally Posted by masters Hi sri340, Use the distance formula to calculate the lengths of each side. $\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ Then add them up. sorry sir i didnt see your reply plz delet my post thanks mrmohamed
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