triangle with vertices

**sri340** · December 2nd 2009, 12:46 PM

What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

**mrmohamed** · December 2nd 2009, 01:01 PM

Originally Posted by sri340

What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi all

the preimeter is 31.7006
the complet solution sooner

**masters** · December 2nd 2009, 01:14 PM

Originally Posted by sri340

What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi sri340,

Use the distance formula to calculate the lengths of each side.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then add them up.

**mrmohamed** · December 2nd 2009, 01:16 PM

Originally Posted by sri340

What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi all

**mrmohamed** · December 2nd 2009, 01:19 PM

Originally Posted by masters

Hi sri340,

Use the distance formula to calculate the lengths of each side.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then add them up.

sorry sir i didnt see your reply
plz delet my post
thanks

mrmohamed

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