# triangle with vertices

• Dec 2nd 2009, 01:46 PM
sri340
triangle with vertices
What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.
• Dec 2nd 2009, 02:01 PM
mrmohamed
Quote:

Originally Posted by sri340
What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi all

the preimeter is 31.7006
the complet solution sooner
• Dec 2nd 2009, 02:14 PM
masters
Quote:

Originally Posted by sri340
What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi sri340,

Use the distance formula to calculate the lengths of each side.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

• Dec 2nd 2009, 02:16 PM
mrmohamed
Quote:

Originally Posted by sri340
What is the perimeter of a triangle with its vertices at (-6, -2), (4, 6), and (2, 10)? Express your answer as a decimal rounded to the nearest tenth.

Hi all

• Dec 2nd 2009, 02:19 PM
mrmohamed
Quote:

Originally Posted by masters
Hi sri340,

Use the distance formula to calculate the lengths of each side.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$