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Math Help - geometry

  1. #1
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    geometry

    area of a triangle with sides of length a,b,and c is given by square root s(s-a)(s-b)(s-c), where s= 1/2(a+b+c) if the lengths of the sides of a triangle are 6,9 and 12 feet, what is the area of the triangle expressed in racical form? Urgent please help me.......
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  2. #2
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    Hello, Schatzle06!

    They gave you the formula and gave you some numbers.
    . . So exactly where is your difficulty?


    The area of a triangle with sides of length a, b,and c is given by:
    . . square root s(s-a)(s-b)(s-c), where s = (a+b+c)/2.

    If the lengths of the sides of a triangle are 6, 9 and 12 feet,
    what is the area of the triangle expressed in radical form?
    I'm embarrassed to do this for you.


    We are given: .a = 6, b = 9, c = 12.

    Then: .s .= .(6 + 9 + 12)/2 .= .27/2

    . . . . . . . . . . . . _______________________________
    Hence: . A . = . √(27/2)(27/2 - 6)(27/2 - 9)(27/2 - 12)
    . . . . . . . . . . . . ___________________
    . . . . . . . . .= . √(27/2)(15/2)(9/2)(3/2)
    . . . . . . . . . . . . ________ . . . . . .__
    . . . . . . . . .= . √10935/16 .= . 27√15/4

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