# geometry

• Feb 19th 2007, 04:54 PM
Schatzle06
geometry
area of a triangle with sides of length a,b,and c is given by square root s(s-a)(s-b)(s-c), where s= 1/2(a+b+c) if the lengths of the sides of a triangle are 6,9 and 12 feet, what is the area of the triangle expressed in racical form? Urgent please help me.......
• Feb 19th 2007, 07:04 PM
Soroban
Hello, Schatzle06!

They gave you the formula and gave you some numbers.
. . So exactly where is your difficulty?

Quote:

The area of a triangle with sides of length a, b,and c is given by:
. . square root s(s-a)(s-b)(s-c), where s = (a+b+c)/2.

If the lengths of the sides of a triangle are 6, 9 and 12 feet,
what is the area of the triangle expressed in radical form?

I'm embarrassed to do this for you.

We are given: .a = 6, b = 9, c = 12.

Then: .s .= .(6 + 9 + 12)/2 .= .27/2

. . . . . . . . . . . . _______________________________
Hence: . A . = . √(27/2)(27/2 - 6)(27/2 - 9)(27/2 - 12)
. . . . . . . . . . . . ___________________
. . . . . . . . .= . √(27/2)(15/2)(9/2)(3/2)
. . . . . . . . . . . . ________ . . . . . .__
. . . . . . . . .= . √10935/16 .= . 27√15/4