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area of a triangle with sides of length a,b,and c is given by square root s(s-a)(s-b)(s-c), where s= 1/2(a+b+c) if the lengths of the sides of a triangle are 6,9 and 12 feet, what is the area of the triangle expressed in racical form? Urgent please help me.......
Hello, Schatzle06!
They gave you the formula and gave you some numbers.
. . So exactly where is your difficulty?
I'm embarrassed to do this for you.Quote:
The area of a triangle with sides of length a, b,and c is given by:
. . square root s(s-a)(s-b)(s-c), where s = (a+b+c)/2.
If the lengths of the sides of a triangle are 6, 9 and 12 feet,
what is the area of the triangle expressed in radical form?
We are given: .a = 6, b = 9, c = 12.
Then: .s .= .(6 + 9 + 12)/2 .= .27/2
. . . . . . . . . . . . _______________________________
Hence: . A . = . √(27/2)(27/2 - 6)(27/2 - 9)(27/2 - 12)
. . . . . . . . . . . . ___________________
. . . . . . . . .= . √(27/2)(15/2)(9/2)(3/2)
. . . . . . . . . . . . ________ . . . . . .__
. . . . . . . . .= . √10935/16 .= . 27√15/4