In triangle ABC , the midpoint of BC is D . THe line that passes through B and parallel to DA intersects CA produced at E . THe line that passes through C and parallel to DA intersects BA produced at F . Prove that BE=CF .
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a is the midpoint of CE and BF from this and with parallel lines it is easy to prove that triangles EBA and ACF are the same and therefor BE = CF can you build on this....
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