1. areas of triangel

In the figure , BA and QR are parallel and CP=PQ=QB , thus AR=1/3 AC . THe lines AQ and BR intersect at L . WRite down the numerical value of the ratio area ARQ to area ACQ and hence prove that area ARQ to area ABC is 2:9 .

I found that the first part to be 1:3 . Not sure with the second part (red) .

2. Let $h$ be the heigth from A in the triangle ABC. Then

$A(ACQ)=\frac{CQ\cdot h}{2}$

$A(ABC)=\frac{BC\cdot h}{2}$

$\frac{A(ACQ)}{A(ABC)}=\frac{CQ}{BC}=\frac{2}{3}$

Now continue.