Let be the heigth from A in the triangle ABC. Then
Now continue.
In the figure , BA and QR are parallel and CP=PQ=QB , thus AR=1/3 AC . THe lines AQ and BR intersect at L . WRite down the numerical value of the ratio area ARQ to area ACQ and hence prove that area ARQ to area ABC is 2:9 .
I found that the first part to be 1:3 . Not sure with the second part (red) .