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Math Help - Aptitude Test coming , Please help !

  1. #1
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    Aptitude Test coming , Please help !

    Hello Guys,
    I have an aptitude test next week and I can not solve the attached problems in Aptitude test.doc , Please help me out with their answers and brief explaintion so i can understand the solution.

    Please don't share any answers that you are not sure of !

    thanks alot
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    Last edited by sous; November 19th 2009 at 12:08 PM.
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by sous View Post
    Hello Guys,
    I have an aptitude test next week and I can not solve the attached problems in Aptitude test.doc , Please help me out with their answers and brief explaintion so i can understand the solution.

    Please don't share any answers that you are not sure of !

    thanks alot
    Hi sous,

    I'll take #2.

    Square A has an area of 64 since each side = 8 (perimeter = 32 given).

    Square B has an area of 36 (given)

    Rectangle D has an area of 2 (given)

    The entire figure has an overall area of 8 X 14 = 112

    Area of C = 112 - 64 -36 - 2 = 10
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  3. #3
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    Almost impossible to help if you don't show your work.
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  4. #4
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    Thanks alot Masters for your respond please let me know if you have any initial idea about other questions.

    for wilmer : thanks for your informative idea,BY the way I am not forcing any one to help me and I am not asking any help from those who doesn't want to help.
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  5. #5
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    Hello All,
    I managed to solve some of the test problems attached in earlier thread , so I wanted to share the answers for practice for others and discuss and confirm my solutions .
    Please if you can explain Q3, Q9, Q10, as I still can not figure them out.

    Q1.
    The Quantity in Column A = Volume of Cube
    The Quantity in Column B = Volume of Cylinder
    Volume of Cube is length * Width* Height = e^3 since cube have equal sides.

    Volume of Cylinder is Πr^2h, since height given = 4/3 e, r=e/2
    Volume of Cylinder = Πe^3/3
    by comparing both volumes ; Then Answer will be the quantity in Column B is greater than the quantity in Column A

    Q2 : Answered in thread above
    Square A has an area of 64 since each side = 8 (perimeter = 32 given).

    Square B has an area of 36 (given)

    Rectangle D has an area of 2 (given)

    The entire figure has an overall area of 8 X 14 = 112

    Area of C = 112 - 64 -36 - 2 = 10


    Q4














    check attached for the shape for better view
    for perimeter , we should calculate all the sides including in the outer shape, given side length equal 3 cm
    a)so there will be 2 squares(upper &lower) of three sides each = 2 ( 3*3)=18
    b)for the mid 2 squares ( right & left ) of two sides each = 2( 2*3) =12
    c)since bottom of any square equal 3 cm and upper or lower line of mid squares equal 9 cm ( 3+3+3) then
    for two small parts left ( upper & lower ) = 2 *3 = 6

    by adding a +b+c = 36

    Q5
    AE║BD, AC║FE, ACCE, and BDCF. so Angle BHC = CHD
    then Ratio of Shaded area / Unshaded area = 2/1

    Q8
    ie : we have 3 dices for Band we need to get sum >16
    so the options are 6*6*6, 6*6*5
    and all possibilities of an B o/p of 3 dices is 3*(6+6+6) =54
    All possibilities of A and B = 108
    then B chances of getting higher than 16 = 2/108 =1/54



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