# Need some measurements

• Feb 11th 2007, 04:23 PM
Movies32
Need some measurements
Attachment 1703

Note that no measurements are equal in length with one another. Please find the measurement for the X's (which are all different lengths).
• Feb 11th 2007, 04:41 PM
topsquark
Quote:

Originally Posted by Movies32
Attachment 1703

Note that no measurements are equal in length with one another. Please find the measurement for the X's (which are all different lengths).

Let's get some of these vertices labelled. I'm going to call the 3 "corners" across the top A B C from left to right, and along the bottom diagonal D E F. Additionally I will call the vertical unknown distance x, the leftmost unknown y, and the rightmost unknown z.

Note that trapezoids ACFD and BCFE are similar, so the sides are in proportion to each other.

Thus:
(80 + 120)/120 = 210/z

Solve for z. I get z = 126. Thus y + z = 210 gives y = 84.

Again:
(80 + 120)/120 = 90/x

I get x = 54.

-Dan
• Feb 11th 2007, 05:00 PM
Movies32
I need the areas for each box please.
• Feb 11th 2007, 05:11 PM
topsquark
Quote:

Originally Posted by Movies32
I need the areas for each box please.

(Shrugs) Each area is a trapezoid. The area of a trapezoid is:
A = (1/2)(b1 + b2)h
where b1 and b2 are the parallel "bases" and h is the perpendicular distance between the bases (the "height"). As these are "right" trapezoids getting the height is easy. And you now have the measurements for each side.

I get the area of trapezoid BCFE is 5040 and the area of trapezoid ACED is 5760.

-Dan