# Thread: Equation of a circle

1. ## Equation of a circle

guys can you help me answer this question and explain how to solve it
Find the equation of a circle given the center is (3, -2) and it is tangent to the x-axis; what about if it is tangent to y-axis

2. if it is tangent to both axes as you said, that centre should be (3, -3) or (2, -2)....isn't it???

3. Hello, FailCalculus!

Please check the wording of the problem.
As stated, there is no solution.

Find the equation of a circle given the center is (3, -2)
and is tangent to the x-axis and tangent to y-axis

The center is at (3, -2).
Code:
        |
|           3
----+-----------+---
|           :
|           :
|           :
-2 + - - - - - *
|

The center is 2 units from the x-axis
- - - - . . and 3 units from the y-axis.

Quite impossible!

4. Originally Posted by ukorov
if it is tangent to both axes as you said, that centre should be (3, -3) or (2, -2)....isn't it???
Originally Posted by Soroban
Hello, FailCalculus!

Please check the wording of the problem.
As stated, there is no solution.

The center is at (3, -2).
Code:
        |
|           3
----+-----------+---
|           :
|           :
|           :
-2 + - - - - - *
|

The center is 2 units from the x-axis
- - - - . . and 3 units from the y-axis.

Quite impossible!

guys im sorry i've check the problem and i admit that i type it wrong . i've already edit it . thanks to both of you

5. For a circle with centre (3, -2) and radius r = 2 units,
$(x - 3)^2 + (y + 2)^2 = 2^2$
$x^2 - 6x + 9 + y^2 + 4y + 4 = 4$
Hence, $x^2 + y^2 - 6x + 4y + 9 = 0$