Thread: Equation of a circle

guys can you help me answer this question and explain how to solve it
Find the equation of a circle given the center is (3, -2) and it is tangent to the x-axis; what about if it is tangent to y-axis

if it is tangent to both axes as you said, that centre should be (3, -3) or (2, -2)....isn't it???

Hello, FailCalculus!

Please check the wording of the problem.
As stated, there is no solution.

Find the equation of a circle given the center is (3, -2)
and is tangent to the x-axis and tangent to y-axis

The center is at (3, -2).

Code:

        |
        |           3
    ----+-----------+---
        |           :
        |           :
        |           :
     -2 + - - - - - *
        |

The center is 2 units from the x-axis
- - - - . . and 3 units from the y-axis.

Quite impossible!

Originally Posted by ukorov

if it is tangent to both axes as you said, that centre should be (3, -3) or (2, -2)....isn't it???

Originally Posted by Soroban

Hello, FailCalculus!

Please check the wording of the problem.
As stated, there is no solution.


The center is at (3, -2).

Code:

        |
        |           3
    ----+-----------+---
        |           :
        |           :
        |           :
     -2 + - - - - - *
        |

The center is 2 units from the x-axis
- - - - . . and 3 units from the y-axis.

Quite impossible!

guys im sorry i've check the problem and i admit that i type it wrong . i've already edit it . thanks to both of you

For a circle with centre (3, -2) and radius r = 2 units,


Hence,