You forgot the absolute values in the perpendicular distance formula
So really, you need to solve , not just
I hope this question goes here.
Heres my question:
The line y-2x+u=0 is 2sqrt5 units from the point (1,-3). Find the possible values of u.
Here is my attempt:
y-2x+u
((-3)-2(1)+u)/√(2^2+1^2 )=2√5
(-5+u)/√5×√5/1=(2√5)/1×√5/1
-5+u=10
u=15 Or u=?
I hope that makes sense, sorry about the mess I dont know how to use the program here.
I can't find the other answer, but I know that the answer is u=15 or u=-5.
Thanks.