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Math Help - geometry (2)

  1. #1
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    geometry (2)

    AB and CD are two equal chords of a circle with centre O , that subtend a right angle at X . P and Q are the midpoints of AB and CD respectively . Prove that OPXQ is a square .
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  2. #2
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    Hello thereddevils
    Quote Originally Posted by thereddevils View Post
    AB and CD are two equal chords of a circle with centre O , that subtend a right angle at X . P and Q are the midpoints of AB and CD respectively . Prove that OPXQ is a square .
    Sorry, this question makes no sense. Have you copied it correctly?

    Grandad
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    the question is misleading....
    simple question on same chords and their same distance to centre of circle.
    OPXQ has 3 right angles, and then PX = QX, PO = QO, so it can only be a square.
    Attached Thumbnails Attached Thumbnails geometry (2)-temp.bmp  
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  4. #4
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    Hello ukorov
    Quote Originally Posted by ukorov View Post
    the question is misleading....
    simple question on same chords and their same distance to centre of circle.
    OPXQ has 3 right angles, and then PX = QX, PO = QO, so it can only be a square.
    If your diagram is correct, then the question is not misleading - it's just plain wrong. Nothing is subtending an angle of 90^o at X. And how do you know that X is the point of intersection of the chords? They are described as AB and CD, not AX and DX.

    Grandad
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  5. #5
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    Quote Originally Posted by Grandad View Post
    Hello thereddevilsSorry, this question makes no sense. Have you copied it correctly?

    Grandad
    Thanks Grandad , I just checked and the question is as it is written in my book . Perhaps the author made a mistake ..
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