prove that in an isosceles trapezium

[sum of parallel sides] x [sum of non parallel sides]= product of diagnols

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- November 6th 2009, 10:21 PMjashansinghalisoscels trapezium
prove that in an isosceles trapezium

[sum of parallel sides] x [sum of non parallel sides]= product of diagnols - November 7th 2009, 03:09 AMBacteriusReply
*A isosceles trapezium named ABCD has just been created from nothing.*The sides (AB) and (CD) are parallel. Therefore, we have :

Note that BC = AD (since the trapezium is isosceles)

Therefore :

Now draw such a trapezium and think of as many useful things as you can : Thales, Pythagoras, Trigonometry, Vectors, anything. Then try putting it all together to substitute formulas into the original equation, so as to prove that the sum of the parallel sides times the sum of the non-parallel sides equals the product of the diagonals. Does it help ? - November 7th 2009, 09:24 PMjashansinghal
sorry,I am not able to understand

- November 7th 2009, 09:37 PMBacterius
What don't you understand ?

- November 7th 2009, 09:48 PMjashansinghal
what do you mean to say?

- November 7th 2009, 09:53 PMBacterius
- November 7th 2009, 10:02 PMjashansinghal
please help me

- November 7th 2009, 10:05 PMWilmer
- November 16th 2009, 08:29 PMjashansinghal
ya...it should be this...but how to proceed

- November 16th 2009, 09:11 PMBacterius
- November 17th 2009, 07:49 AMjashansinghal
prove that in an isosceles trapezium

[sum of parallel sides] x [sum of non parallel sides]= product of diagnols - November 17th 2009, 04:12 PMBacterius
- November 18th 2009, 08:54 AMjashansinghal
please help me....can you do first few steps

- November 21st 2009, 03:16 PMaidan